Base | Representation |
---|---|
bin | 11101011101000111001… |
… | …100010010110000110011 |
3 | 21011111121200102002111212 |
4 | 131131013030102300303 |
5 | 231130401221020311 |
6 | 4145511510030335 |
7 | 266144452063325 |
oct | 35350714226063 |
9 | 7144550362455 |
10 | 2024124001331 |
11 | 710476259073 |
12 | 2883570483ab |
13 | 118b49458983 |
14 | 6dd7a767615 |
15 | 379bad14c8b |
hex | 1d747312c33 |
2024124001331 has 2 divisors, whose sum is σ = 2024124001332. Its totient is φ = 2024124001330.
The previous prime is 2024124001301. The next prime is 2024124001369. The reversal of 2024124001331 is 1331004214202.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2024124001331 - 210 = 2024124000307 is a prime.
It is a super-2 number, since 2×20241240013312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 2024124001297 and 2024124001306.
It is not a weakly prime, because it can be changed into another prime (2024124001301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1012062000665 + 1012062000666.
It is an arithmetic number, because the mean of its divisors is an integer number (1012062000666).
Almost surely, 22024124001331 is an apocalyptic number.
2024124001331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2024124001331 is an equidigital number, since it uses as much as digits as its factorization.
2024124001331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 2024124001331 its reverse (1331004214202), we get a palindrome (3355128215533).
The spelling of 2024124001331 in words is "two trillion, twenty-four billion, one hundred twenty-four million, one thousand, three hundred thirty-one".
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