Base | Representation |
---|---|
bin | 1001001101010111111100… |
… | …11001001110111100010011 |
3 | 2122200221201011021102020211 |
4 | 10212223332121032330103 |
5 | 10123242010412023021 |
6 | 111023021401144551 |
7 | 4160032211461426 |
oct | 446537631167423 |
9 | 78627634242224 |
10 | 20250743861011 |
11 | 64a8323a79054 |
12 | 233089118b157 |
13 | b3b8384cb071 |
14 | 5001d97839bd |
15 | 251b7d1383e1 |
hex | 126afe64ef13 |
20250743861011 has 2 divisors, whose sum is σ = 20250743861012. Its totient is φ = 20250743861010.
The previous prime is 20250743861003. The next prime is 20250743861027. The reversal of 20250743861011 is 11016834705202.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20250743861011 - 23 = 20250743861003 is a prime.
It is not a weakly prime, because it can be changed into another prime (20250743861071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10125371930505 + 10125371930506.
It is an arithmetic number, because the mean of its divisors is an integer number (10125371930506).
Almost surely, 220250743861011 is an apocalyptic number.
20250743861011 is a deficient number, since it is larger than the sum of its proper divisors (1).
20250743861011 is an equidigital number, since it uses as much as digits as its factorization.
20250743861011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 40.
The spelling of 20250743861011 in words is "twenty trillion, two hundred fifty billion, seven hundred forty-three million, eight hundred sixty-one thousand, eleven".
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