Base | Representation |
---|---|
bin | 1001001101011000111000… |
… | …01101100111100100101111 |
3 | 2122201000000000121211221020 |
4 | 10212230130031213210233 |
5 | 10123244021444221110 |
6 | 111023143151505223 |
7 | 4160050464636354 |
oct | 446543415474457 |
9 | 78630000554836 |
10 | 20251244132655 |
11 | 64a8560400598 |
12 | 23309b0828213 |
13 | b3b8b80499a3 |
14 | 500245daa62b |
15 | 251bac006d70 |
hex | 126b1c36792f |
20251244132655 has 64 divisors (see below), whose sum is σ = 33570316892160. Its totient is φ = 10412363275776.
The previous prime is 20251244132621. The next prime is 20251244132657. The reversal of 20251244132655 is 55623144215202.
It is not a de Polignac number, because 20251244132655 - 27 = 20251244132527 is a prime.
It is a super-2 number, since 2×202512441326552 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20251244132657) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1559821294 + ... + 1559834276.
It is an arithmetic number, because the mean of its divisors is an integer number (524536201440).
Almost surely, 220251244132655 is an apocalyptic number.
20251244132655 is a deficient number, since it is larger than the sum of its proper divisors (13319072759505).
20251244132655 is a wasteful number, since it uses less digits than its factorization.
20251244132655 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18200.
The product of its (nonzero) digits is 576000, while the sum is 42.
Adding to 20251244132655 its reverse (55623144215202), we get a palindrome (75874388347857).
The spelling of 20251244132655 in words is "twenty trillion, two hundred fifty-one billion, two hundred forty-four million, one hundred thirty-two thousand, six hundred fifty-five".
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