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20252011677451 is a prime number
BaseRepresentation
bin1001001101011010010011…
…11101100100011100001011
32122201001222111220011110021
410212231021331210130023
510123302104442134301
6111023351251001311
74160105504650321
oct446551175443413
978631874804407
1020252011677451
1164a8914694334
122330b85899237
13b3b9ab0781c8
145002b9cc7d11
15251c045bc8a1
hex126b49f6470b

20252011677451 has 2 divisors, whose sum is σ = 20252011677452. Its totient is φ = 20252011677450.

The previous prime is 20252011677311. The next prime is 20252011677473. The reversal of 20252011677451 is 15477611025202.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20252011677451 - 213 = 20252011669259 is a prime.

It is a super-2 number, since 2×202520116774512 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20252011677398 and 20252011677407.

It is not a weakly prime, because it can be changed into another prime (20252011674451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10126005838725 + 10126005838726.

It is an arithmetic number, because the mean of its divisors is an integer number (10126005838726).

Almost surely, 220252011677451 is an apocalyptic number.

20252011677451 is a deficient number, since it is larger than the sum of its proper divisors (1).

20252011677451 is an equidigital number, since it uses as much as digits as its factorization.

20252011677451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 235200, while the sum is 43.

The spelling of 20252011677451 in words is "twenty trillion, two hundred fifty-two billion, eleven million, six hundred seventy-seven thousand, four hundred fifty-one".