Base | Representation |
---|---|
bin | 101110000011000110101000… |
… | …000110010000110001011101 |
3 | 222120002001022212121110101220 |
4 | 232003012220012100301131 |
5 | 203021120422224402031 |
6 | 1554421545510123553 |
7 | 60441555655045446 |
oct | 5603065006206135 |
9 | 876061285543356 |
10 | 202523413122141 |
11 | 59591773a29851 |
12 | 1a86a4893505b9 |
13 | 8900b504b7437 |
14 | 38022850042cd |
15 | 18631733b6596 |
hex | b831a8190c5d |
202523413122141 has 8 divisors (see below), whose sum is σ = 279342638789280. Its totient is φ = 130359898101552.
The previous prime is 202523413122101. The next prime is 202523413122157. The reversal of 202523413122141 is 141221314325202.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 202523413122141 - 217 = 202523412991069 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (202523413122101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1163927661535 + ... + 1163927661708.
It is an arithmetic number, because the mean of its divisors is an integer number (34917829848660).
Almost surely, 2202523413122141 is an apocalyptic number.
It is an amenable number.
202523413122141 is a deficient number, since it is larger than the sum of its proper divisors (76819225667139).
202523413122141 is a wasteful number, since it uses less digits than its factorization.
202523413122141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2327855323275.
The product of its (nonzero) digits is 23040, while the sum is 33.
Adding to 202523413122141 its reverse (141221314325202), we get a palindrome (343744727447343).
The spelling of 202523413122141 in words is "two hundred two trillion, five hundred twenty-three billion, four hundred thirteen million, one hundred twenty-two thousand, one hundred forty-one".
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