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202523413122157 is a prime number
BaseRepresentation
bin101110000011000110101000…
…000110010000110001101101
3222120002001022212121110102111
4232003012220012100301231
5203021120422224402112
61554421545510124021
760441555655045501
oct5603065006206155
9876061285543374
10202523413122157
1159591773a29866
121a86a489350611
138900b504b744a
143802285004301
1518631733b65a7
hexb831a8190c6d

202523413122157 has 2 divisors, whose sum is σ = 202523413122158. Its totient is φ = 202523413122156.

The previous prime is 202523413122101. The next prime is 202523413122187. The reversal of 202523413122157 is 751221314325202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 183561472892196 + 18961940229961 = 13548486^2 + 4354531^2 .

It is a cyclic number.

It is not a de Polignac number, because 202523413122157 - 247 = 61785924766829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (202523413122187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101261706561078 + 101261706561079.

It is an arithmetic number, because the mean of its divisors is an integer number (101261706561079).

Almost surely, 2202523413122157 is an apocalyptic number.

It is an amenable number.

202523413122157 is a deficient number, since it is larger than the sum of its proper divisors (1).

202523413122157 is an equidigital number, since it uses as much as digits as its factorization.

202523413122157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 201600, while the sum is 40.

Adding to 202523413122157 its reverse (751221314325202), we get a palindrome (953744727447359).

The spelling of 202523413122157 in words is "two hundred two trillion, five hundred twenty-three billion, four hundred thirteen million, one hundred twenty-two thousand, one hundred fifty-seven".