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202523413122143 = 1105718316307599
BaseRepresentation
bin101110000011000110101000…
…000110010000110001011111
3222120002001022212121110101222
4232003012220012100301133
5203021120422224402033
61554421545510123555
760441555655045451
oct5603065006206137
9876061285543358
10202523413122143
1159591773a29853
121a86a4893505bb
138900b504b7439
1438022850042d1
1518631733b6598
hexb831a8190c5f

202523413122143 has 4 divisors (see below), whose sum is σ = 202541729440800. Its totient is φ = 202505096803488.

The previous prime is 202523413122101. The next prime is 202523413122157. The reversal of 202523413122143 is 341221314325202.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 202523413122143 - 234 = 202506233252959 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (202523413122343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9158142743 + ... + 9158164856.

It is an arithmetic number, because the mean of its divisors is an integer number (50635432360200).

Almost surely, 2202523413122143 is an apocalyptic number.

202523413122143 is a deficient number, since it is larger than the sum of its proper divisors (18316318657).

202523413122143 is a wasteful number, since it uses less digits than its factorization.

202523413122143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18316318656.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 202523413122143 its reverse (341221314325202), we get a palindrome (543744727447345).

The spelling of 202523413122143 in words is "two hundred two trillion, five hundred twenty-three billion, four hundred thirteen million, one hundred twenty-two thousand, one hundred forty-three".

Divisors: 1 11057 18316307599 202523413122143