Base | Representation |
---|---|
bin | 11101011110001001111… |
… | …001100011000110110111 |
3 | 21011121111200022021222112 |
4 | 131132021321203012313 |
5 | 231140144222123030 |
6 | 4150214525321235 |
7 | 266214261555464 |
oct | 35361171430667 |
9 | 7147450267875 |
10 | 2025243161015 |
11 | 71099aa6a328 |
12 | 288609a0621b |
13 | 118c97287439 |
14 | 7004525266b |
15 | 37a341d2a95 |
hex | 1d789e631b7 |
2025243161015 has 8 divisors (see below), whose sum is σ = 2457598443120. Its totient is φ = 1601990095552.
The previous prime is 2025243161003. The next prime is 2025243161021. The reversal of 2025243161015 is 5101613425202.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2025243161015 - 240 = 925731533239 is a prime.
It is a super-2 number, since 2×20252431610152 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2275553669 + ... + 2275554558.
It is an arithmetic number, because the mean of its divisors is an integer number (307199805390).
Almost surely, 22025243161015 is an apocalyptic number.
2025243161015 is a deficient number, since it is larger than the sum of its proper divisors (432355282105).
2025243161015 is an equidigital number, since it uses as much as digits as its factorization.
2025243161015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4551108321.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 2025243161015 its reverse (5101613425202), we get a palindrome (7126856586217).
The spelling of 2025243161015 in words is "two trillion, twenty-five billion, two hundred forty-three million, one hundred sixty-one thousand, fifteen".
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