Base | Representation |
---|---|
bin | 10010110111001001… |
… | …000011000000100111 |
3 | 1221021102121010210221 |
4 | 102313021003000213 |
5 | 312434113040320 |
6 | 13145344425211 |
7 | 1314606110635 |
oct | 226711030047 |
9 | 57242533727 |
10 | 20252471335 |
11 | 8652aa0518 |
12 | 3b12618207 |
13 | 1ba9aa4165 |
14 | da1a46355 |
15 | 7d7edc3aa |
hex | 4b7243027 |
20252471335 has 8 divisors (see below), whose sum is σ = 24340765680. Its totient is φ = 16176777024.
The previous prime is 20252471333. The next prime is 20252471339. The reversal of 20252471335 is 53317425202.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 20252471335 - 21 = 20252471333 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20252471335.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20252471333) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3146470 + ... + 3152899.
It is an arithmetic number, because the mean of its divisors is an integer number (3042595710).
Almost surely, 220252471335 is an apocalyptic number.
20252471335 is a deficient number, since it is larger than the sum of its proper divisors (4088294345).
20252471335 is an equidigital number, since it uses as much as digits as its factorization.
20252471335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6300017.
The product of its (nonzero) digits is 50400, while the sum is 34.
Adding to 20252471335 its reverse (53317425202), we get a palindrome (73569896537).
The spelling of 20252471335 in words is "twenty billion, two hundred fifty-two million, four hundred seventy-one thousand, three hundred thirty-five".
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