Base | Representation |
---|---|
bin | 11101011110010011011… |
… | …000000010110010011001 |
3 | 21011121220202110202220222 |
4 | 131132103120002302121 |
5 | 231141010422300131 |
6 | 4150242405125425 |
7 | 266221232134364 |
oct | 35362330026231 |
9 | 7147822422828 |
10 | 2025402150041 |
11 | 710a71791116 |
12 | 2886530b9875 |
13 | 118cc11b299a |
14 | 7005c3db0db |
15 | 37a4313a87b |
hex | 1d793602c99 |
2025402150041 has 2 divisors, whose sum is σ = 2025402150042. Its totient is φ = 2025402150040.
The previous prime is 2025402149951. The next prime is 2025402150047. The reversal of 2025402150041 is 1400512045202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1636618724416 + 388783425625 = 1279304^2 + 623525^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2025402150041 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (2025402150047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1012701075020 + 1012701075021.
It is an arithmetic number, because the mean of its divisors is an integer number (1012701075021).
Almost surely, 22025402150041 is an apocalyptic number.
It is an amenable number.
2025402150041 is a deficient number, since it is larger than the sum of its proper divisors (1).
2025402150041 is an equidigital number, since it uses as much as digits as its factorization.
2025402150041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3200, while the sum is 26.
Adding to 2025402150041 its reverse (1400512045202), we get a palindrome (3425914195243).
The spelling of 2025402150041 in words is "two trillion, twenty-five billion, four hundred two million, one hundred fifty thousand, forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •