2025402150433 has 2 divisors, whose sum is σ = 2025402150434. Its totient is φ = 2025402150432.

The previous prime is 2025402150419. The next prime is 2025402150451. The reversal of 2025402150433 is 3340512045202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1842827970064 + 182574180369 = 1357508^2 + 427287^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2025402150433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2025402150395 and 2025402150404.

It is not a weakly prime, because it can be changed into another prime (2025402151433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1012701075216 + 1012701075217.

It is an arithmetic number, because the mean of its divisors is an integer number (1012701075217).

Almost surely, 2^{2025402150433} is an apocalyptic number.

It is an amenable number.

2025402150433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2025402150433 is an equidigital number, since it uses as much as digits as its factorization.

2025402150433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 2025402150433 its reverse (3340512045202), we get a palindrome (5365914195635).

The spelling of 2025402150433 in words is "two trillion, twenty-five billion, four hundred two million, one hundred fifty thousand, four hundred thirty-three".