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2025412043133 = 31494531123139
BaseRepresentation
bin11101011110010011111…
…101110010000101111101
321011121221110002101200210
4131132103331302011331
5231141020440340013
64150243401143033
7266221412210253
oct35362375620575
97147843071623
102025412043133
11710a77328a26
1228865648aa79
13118cc326799b
147005d8545d3
1537a43e41cc3
hex1d793f7217d

2025412043133 has 8 divisors (see below), whose sum is σ = 2718673884000. Its totient is φ = 1341212448848.

The previous prime is 2025412043047. The next prime is 2025412043153. The reversal of 2025412043133 is 3313402145202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2025412043133 - 28 = 2025412042877 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2025412043133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2025412043153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2265561123 + ... + 2265562016.

It is an arithmetic number, because the mean of its divisors is an integer number (339834235500).

Almost surely, 22025412043133 is an apocalyptic number.

It is an amenable number.

2025412043133 is a deficient number, since it is larger than the sum of its proper divisors (693261840867).

2025412043133 is a wasteful number, since it uses less digits than its factorization.

2025412043133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4531123291.

The product of its (nonzero) digits is 17280, while the sum is 30.

Adding to 2025412043133 its reverse (3313402145202), we get a palindrome (5338814188335).

The spelling of 2025412043133 in words is "two trillion, twenty-five billion, four hundred twelve million, forty-three thousand, one hundred thirty-three".

Divisors: 1 3 149 447 4531123139 13593369417 675137347711 2025412043133