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202542251033 is a prime number
BaseRepresentation
bin1011110010100001110…
…1010111110000011001
3201100210111222102022002
42330220131113300121
511304301304013113
6233014023210345
720430120504413
oct2745035276031
9640714872262
10202542251033
1178996903011
1233306ba69b5
131613ac22925
149b359ad9b3
155406748c58
hex2f28757c19

202542251033 has 2 divisors, whose sum is σ = 202542251034. Its totient is φ = 202542251032.

The previous prime is 202542251017. The next prime is 202542251053. The reversal of 202542251033 is 330152245202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 163089168649 + 39453082384 = 403843^2 + 198628^2 .

It is a cyclic number.

It is not a de Polignac number, because 202542251033 - 24 = 202542251017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 202542250987 and 202542251005.

It is not a weakly prime, because it can be changed into another prime (202542251053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101271125516 + 101271125517.

It is an arithmetic number, because the mean of its divisors is an integer number (101271125517).

Almost surely, 2202542251033 is an apocalyptic number.

It is an amenable number.

202542251033 is a deficient number, since it is larger than the sum of its proper divisors (1).

202542251033 is an equidigital number, since it uses as much as digits as its factorization.

202542251033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 29.

Adding to 202542251033 its reverse (330152245202), we get a palindrome (532694496235).

The spelling of 202542251033 in words is "two hundred two billion, five hundred forty-two million, two hundred fifty-one thousand, thirty-three".