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2025451031041 is a prime number
BaseRepresentation
bin11101011110010110010…
…010100000101000000001
321011122001011110012001101
4131132112102200220001
5231141110430443131
64150251312534401
7266222364461524
oct35362622405001
97148034405041
102025451031041
11710a97338139
12288667551401
13118ccb368959
1470064ac2bbb
1537a47593c61
hex1d7964a0a01

2025451031041 has 2 divisors, whose sum is σ = 2025451031042. Its totient is φ = 2025451031040.

The previous prime is 2025451031033. The next prime is 2025451031057. The reversal of 2025451031041 is 1401301545202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1420160807025 + 605290224016 = 1191705^2 + 778004^2 .

It is a cyclic number.

It is not a de Polignac number, because 2025451031041 - 23 = 2025451031033 is a prime.

It is not a weakly prime, because it can be changed into another prime (2025451031141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1012725515520 + 1012725515521.

It is an arithmetic number, because the mean of its divisors is an integer number (1012725515521).

Almost surely, 22025451031041 is an apocalyptic number.

It is an amenable number.

2025451031041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2025451031041 is an equidigital number, since it uses as much as digits as its factorization.

2025451031041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 2025451031041 its reverse (1401301545202), we get a palindrome (3426752576243).

The spelling of 2025451031041 in words is "two trillion, twenty-five billion, four hundred fifty-one million, thirty-one thousand, forty-one".