Base | Representation |
---|---|
bin | 11101011110110100100… |
… | …000111010011110011001 |
3 | 21011200100111122011000111 |
4 | 131132310200322132121 |
5 | 231143130234422132 |
6 | 4150413505404321 |
7 | 266241062625124 |
oct | 35366440723631 |
9 | 7150314564014 |
10 | 2025958123417 |
11 | 7112275a9148 |
12 | 2887893396a1 |
13 | 11907c435007 |
14 | 700b21a33bb |
15 | 37a76d5d647 |
hex | 1d7b483a799 |
2025958123417 has 2 divisors, whose sum is σ = 2025958123418. Its totient is φ = 2025958123416.
The previous prime is 2025958123379. The next prime is 2025958123429. The reversal of 2025958123417 is 7143218595202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1036372864576 + 989585258841 = 1018024^2 + 994779^2 .
It is a cyclic number.
It is not a de Polignac number, because 2025958123417 - 215 = 2025958090649 is a prime.
It is not a weakly prime, because it can be changed into another prime (2025958123477) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1012979061708 + 1012979061709.
It is an arithmetic number, because the mean of its divisors is an integer number (1012979061709).
Almost surely, 22025958123417 is an apocalyptic number.
It is an amenable number.
2025958123417 is a deficient number, since it is larger than the sum of its proper divisors (1).
2025958123417 is an equidigital number, since it uses as much as digits as its factorization.
2025958123417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1209600, while the sum is 49.
The spelling of 2025958123417 in words is "two trillion, twenty-five billion, nine hundred fifty-eight million, one hundred twenty-three thousand, four hundred seventeen".
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