Base | Representation |
---|---|
bin | 11101100011001111001… |
… | …111010001011100001001 |
3 | 21012010121002001011020111 |
4 | 131203033033101130021 |
5 | 231232334032413032 |
6 | 4152520311354321 |
7 | 266466450350431 |
oct | 35431717213411 |
9 | 7163532034214 |
10 | 2030701451017 |
11 | 7132410353a8 |
12 | 2896919829a1 |
13 | 119657056135 |
14 | 7040212d2c1 |
15 | 37c534b3c47 |
hex | 1d8cf3d1709 |
2030701451017 has 2 divisors, whose sum is σ = 2030701451018. Its totient is φ = 2030701451016.
The previous prime is 2030701450957. The next prime is 2030701451029. The reversal of 2030701451017 is 7101541070302.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2010769376256 + 19932074761 = 1418016^2 + 141181^2 .
It is a cyclic number.
It is not a de Polignac number, because 2030701451017 - 235 = 1996341712649 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2030701451017.
It is not a weakly prime, because it can be changed into another prime (2030701451617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1015350725508 + 1015350725509.
It is an arithmetic number, because the mean of its divisors is an integer number (1015350725509).
Almost surely, 22030701451017 is an apocalyptic number.
It is an amenable number.
2030701451017 is a deficient number, since it is larger than the sum of its proper divisors (1).
2030701451017 is an equidigital number, since it uses as much as digits as its factorization.
2030701451017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5880, while the sum is 31.
The spelling of 2030701451017 in words is "two trillion, thirty billion, seven hundred one million, four hundred fifty-one thousand, seventeen".
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