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203113114131200 = 2852713502369431
BaseRepresentation
bin101110001011101011110101…
…000001000101101100000000
3222122011102110011002120022012
4232023223311001011230000
5203110301124204144300
61555552513153232052
760532303212654020
oct5613536501055400
9878142404076265
10203113114131200
1159799873862a89
121a944822b62628
13894463b520a60
143822a27535a80
151873688eb6435
hexb8baf5045b00

203113114131200 has 432 divisors, whose sum is σ = 618884951494656. Its totient is φ = 64268229427200.

The previous prime is 203113114131197. The next prime is 203113114131247. The reversal of 203113114131200 is 2131411311302.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2925360485 + ... + 2925429915.

Almost surely, 2203113114131200 is an apocalyptic number.

203113114131200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 203113114131200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (309442475747328).

203113114131200 is an abundant number, since it is smaller than the sum of its proper divisors (415771837363456).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

203113114131200 is a wasteful number, since it uses less digits than its factorization.

203113114131200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 74500 (or 74481 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 203113114131200 its reverse (2131411311302), we get a palindrome (205244525442502).

The spelling of 203113114131200 in words is "two hundred three trillion, one hundred thirteen billion, one hundred fourteen million, one hundred thirty-one thousand, two hundred".