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20311314113 is a prime number
BaseRepresentation
bin10010111010101001…
…100000111011000001
31221102112022122221002
4102322221200323001
5313044144022423
613155245541345
71316222215136
oct227251407301
957375278832
1020311314113
118683230a12
123b2a274855
131bb903747c
14da97a258d
157dd262228
hex4baa60ec1

20311314113 has 2 divisors, whose sum is σ = 20311314114. Its totient is φ = 20311314112.

The previous prime is 20311314109. The next prime is 20311314131. The reversal of 20311314113 is 31141311302.

Together with next prime (20311314131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11955891649 + 8355422464 = 109343^2 + 91408^2 .

It is a cyclic number.

It is not a de Polignac number, because 20311314113 - 22 = 20311314109 is a prime.

It is not a weakly prime, because it can be changed into another prime (20311314313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10155657056 + 10155657057.

It is an arithmetic number, because the mean of its divisors is an integer number (10155657057).

Almost surely, 220311314113 is an apocalyptic number.

It is an amenable number.

20311314113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20311314113 is an equidigital number, since it uses as much as digits as its factorization.

20311314113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 20311314113 its reverse (31141311302), we get a palindrome (51452625415).

The spelling of 20311314113 in words is "twenty billion, three hundred eleven million, three hundred fourteen thousand, one hundred thirteen".