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2031143442001 = 13115504911771
BaseRepresentation
bin11101100011101001100…
…101010101011001010001
321012011201212201121212221
4131203221211111121101
5231234240210121001
64153032221021041
7266513425252042
oct35435145253121
97164655647787
102031143442001
11713448580803
122897959b4781
131196c77aa56b
1470444b048c9
1537c7c1be1a1
hex1d8e9955651

2031143442001 has 4 divisors (see below), whose sum is σ = 2046648353904. Its totient is φ = 2015638530100.

The previous prime is 2031143441989. The next prime is 2031143442047. The reversal of 2031143442001 is 1002443411302.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2031143442001 - 221 = 2031141344849 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2031143442091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7752455755 + ... + 7752456016.

It is an arithmetic number, because the mean of its divisors is an integer number (511662088476).

Almost surely, 22031143442001 is an apocalyptic number.

It is an amenable number.

2031143442001 is a deficient number, since it is larger than the sum of its proper divisors (15504911903).

2031143442001 is a wasteful number, since it uses less digits than its factorization.

2031143442001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15504911902.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 2031143442001 its reverse (1002443411302), we get a palindrome (3033586853303).

The spelling of 2031143442001 in words is "two trillion, thirty-one billion, one hundred forty-three million, four hundred forty-two thousand, one".

Divisors: 1 131 15504911771 2031143442001