Base | Representation |
---|---|
bin | 1001001111001101111110… |
… | …10101100000110011110011 |
3 | 2122221000021021122200002002 |
4 | 10213212333111200303303 |
5 | 10130311244232233301 |
6 | 111112101250444215 |
7 | 4164434410436405 |
oct | 447467725406363 |
9 | 78830237580062 |
10 | 20314110430451 |
11 | 6522190828602 |
12 | 234101659366b |
13 | b447c6577776 |
14 | 5032cb3c0b75 |
15 | 25363b1dd16b |
hex | 1279bf560cf3 |
20314110430451 has 2 divisors, whose sum is σ = 20314110430452. Its totient is φ = 20314110430450.
The previous prime is 20314110430447. The next prime is 20314110430483. The reversal of 20314110430451 is 15403401141302.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20314110430451 - 22 = 20314110430447 is a prime.
It is a super-3 number, since 3×203141104304513 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (20314110430351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10157055215225 + 10157055215226.
It is an arithmetic number, because the mean of its divisors is an integer number (10157055215226).
Almost surely, 220314110430451 is an apocalyptic number.
20314110430451 is a deficient number, since it is larger than the sum of its proper divisors (1).
20314110430451 is an equidigital number, since it uses as much as digits as its factorization.
20314110430451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 20314110430451 its reverse (15403401141302), we get a palindrome (35717511571753).
The spelling of 20314110430451 in words is "twenty trillion, three hundred fourteen billion, one hundred ten million, four hundred thirty thousand, four hundred fifty-one".
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