Base | Representation |
---|---|
bin | 1001001111110011000110… |
… | …11011110010111111100011 |
3 | 2122222220201110001222002211 |
4 | 10213321203123302333203 |
5 | 10131123110103113103 |
6 | 111125155223422551 |
7 | 4166041360120522 |
oct | 447714333627743 |
9 | 78886643058084 |
10 | 20334043410403 |
11 | 652a68a441458 |
12 | 2344a59bb4a57 |
13 | b466520b8068 |
14 | 50425c81c4b9 |
15 | 253e0611b36d |
hex | 127e636f2fe3 |
20334043410403 has 2 divisors, whose sum is σ = 20334043410404. Its totient is φ = 20334043410402.
The previous prime is 20334043410383. The next prime is 20334043410449. The reversal of 20334043410403 is 30401434043302.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20334043410403 - 217 = 20334043279331 is a prime.
It is not a weakly prime, because it can be changed into another prime (20334043411403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10167021705201 + 10167021705202.
It is an arithmetic number, because the mean of its divisors is an integer number (10167021705202).
Almost surely, 220334043410403 is an apocalyptic number.
20334043410403 is a deficient number, since it is larger than the sum of its proper divisors (1).
20334043410403 is an equidigital number, since it uses as much as digits as its factorization.
20334043410403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 20334043410403 its reverse (30401434043302), we get a palindrome (50735477453705).
The spelling of 20334043410403 in words is "twenty trillion, three hundred thirty-four billion, forty-three million, four hundred ten thousand, four hundred three".
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