Base | Representation |
---|---|
bin | 10010111100011010… |
… | …110011001111101001 |
3 | 1221111121012102222211 |
4 | 102330122303033221 |
5 | 313124244331213 |
6 | 13202230245121 |
7 | 1320032513221 |
oct | 227432631751 |
9 | 57447172884 |
10 | 20341011433 |
11 | 8698a74a56 |
12 | 3b381b67a1 |
13 | 1bc2234752 |
14 | dad6d3081 |
15 | 7e0b7b53d |
hex | 4bc6b33e9 |
20341011433 has 2 divisors, whose sum is σ = 20341011434. Its totient is φ = 20341011432.
The previous prime is 20341011401. The next prime is 20341011443. The reversal of 20341011433 is 33411014302.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18853212249 + 1487799184 = 137307^2 + 38572^2 .
It is a cyclic number.
It is not a de Polignac number, because 20341011433 - 25 = 20341011401 is a prime.
It is a super-2 number, since 2×203410114332 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20341011443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10170505716 + 10170505717.
It is an arithmetic number, because the mean of its divisors is an integer number (10170505717).
Almost surely, 220341011433 is an apocalyptic number.
It is an amenable number.
20341011433 is a deficient number, since it is larger than the sum of its proper divisors (1).
20341011433 is an equidigital number, since it uses as much as digits as its factorization.
20341011433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 20341011433 its reverse (33411014302), we get a palindrome (53752025735).
The spelling of 20341011433 in words is "twenty billion, three hundred forty-one million, eleven thousand, four hundred thirty-three".
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