Base | Representation |
---|---|
bin | 10011000000000011… |
… | …011101000100000011 |
3 | 1221122211221222202111 |
4 | 103000003131010003 |
5 | 313240403001011 |
6 | 13212245400151 |
7 | 1321403065642 |
oct | 230003350403 |
9 | 57584858674 |
10 | 20402000131 |
11 | 871a440737 |
12 | 3b54709057 |
13 | 1c01a69736 |
14 | db784b359 |
15 | 7e61c7121 |
hex | 4c00dd103 |
20402000131 has 2 divisors, whose sum is σ = 20402000132. Its totient is φ = 20402000130.
The previous prime is 20402000077. The next prime is 20402000137. The reversal of 20402000131 is 13100020402.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20402000131 - 211 = 20401998083 is a prime.
It is a super-2 number, since 2×204020001312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20402000137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10201000065 + 10201000066.
It is an arithmetic number, because the mean of its divisors is an integer number (10201000066).
Almost surely, 220402000131 is an apocalyptic number.
20402000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
20402000131 is an equidigital number, since it uses as much as digits as its factorization.
20402000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 20402000131 its reverse (13100020402), we get a palindrome (33502020533).
The spelling of 20402000131 in words is "twenty billion, four hundred two million, one hundred thirty-one", and thus it is an aban number.
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