Base | Representation |
---|---|
bin | 1001010001110001111001… |
… | …10000111111010011100011 |
3 | 2200020102102102010212102001 |
4 | 10220320330300333103203 |
5 | 10133232012204144141 |
6 | 111220333555304431 |
7 | 4204001256523423 |
oct | 450707460772343 |
9 | 80212372125361 |
10 | 20402114131171 |
11 | 65565405aa483 |
12 | 23560968ab117 |
13 | b4cbac919c66 |
14 | 507679108483 |
15 | 255a8c188a31 |
hex | 128e3cc3f4e3 |
20402114131171 has 2 divisors, whose sum is σ = 20402114131172. Its totient is φ = 20402114131170.
The previous prime is 20402114131163. The next prime is 20402114131177. The reversal of 20402114131171 is 17113141120402.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20402114131171 - 23 = 20402114131163 is a prime.
It is a super-2 number, since 2×204021141311712 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20402114131177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10201057065585 + 10201057065586.
It is an arithmetic number, because the mean of its divisors is an integer number (10201057065586).
Almost surely, 220402114131171 is an apocalyptic number.
20402114131171 is a deficient number, since it is larger than the sum of its proper divisors (1).
20402114131171 is an equidigital number, since it uses as much as digits as its factorization.
20402114131171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 28.
Adding to 20402114131171 its reverse (17113141120402), we get a palindrome (37515255251573).
The spelling of 20402114131171 in words is "twenty trillion, four hundred two billion, one hundred fourteen million, one hundred thirty-one thousand, one hundred seventy-one".
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