204034123113133 has 24 divisors (see below), whose sum is σ = 221582763012672. Its totient is φ = 187785188980224.

The previous prime is 204034123113131. The next prime is 204034123113173. The reversal of 204034123113133 is 331311321430402.

204034123113133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 204034123113133 - 2¹ = 204034123113131 is a prime.

It is a super-2 number, since 2×204034123113133² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 204034123113095 and 204034123113104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (204034123113131) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 35804641 + ... + 41110102.

It is an arithmetic number, because the mean of its divisors is an integer number (9232615125528).

Almost surely, 2^{204034123113133} is an apocalyptic number.

It is an amenable number.

204034123113133 is a deficient number, since it is larger than the sum of its proper divisors (17548639899539).

204034123113133 is a wasteful number, since it uses less digits than its factorization.

204034123113133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76914981 (or 76914964 counting only the distinct ones).

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 204034123113133 its reverse (331311321430402), we get a palindrome (535345444543535).

The spelling of 204034123113133 in words is "two hundred four trillion, thirty-four billion, one hundred twenty-three million, one hundred thirteen thousand, one hundred thirty-three".