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20404341131 is a prime number
BaseRepresentation
bin10011000000001100…
…011000100110001011
31221200000100221000012
4103000030120212023
5313242002404011
613212411502135
71321432016006
oct230014304613
957600327005
1020404341131
11872079a549
123b5545794b
131c023a9145
14db7c9a53d
157e64daa8b
hex4c031898b

20404341131 has 2 divisors, whose sum is σ = 20404341132. Its totient is φ = 20404341130.

The previous prime is 20404341127. The next prime is 20404341149. The reversal of 20404341131 is 13114340402.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20404341131 - 22 = 20404341127 is a prime.

It is a super-2 number, since 2×204043411312 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 20404341097 and 20404341106.

It is not a weakly prime, because it can be changed into another prime (20404341151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10202170565 + 10202170566.

It is an arithmetic number, because the mean of its divisors is an integer number (10202170566).

Almost surely, 220404341131 is an apocalyptic number.

20404341131 is a deficient number, since it is larger than the sum of its proper divisors (1).

20404341131 is an equidigital number, since it uses as much as digits as its factorization.

20404341131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 20404341131 its reverse (13114340402), we get a palindrome (33518681533).

The spelling of 20404341131 in words is "twenty billion, four hundred four million, three hundred forty-one thousand, one hundred thirty-one".