Base | Representation |
---|---|
bin | 1001010010000110011101… |
… | …10100100001000111011001 |
3 | 2200021110220211110220011222 |
4 | 10221003032310201013121 |
5 | 10133422120020323332 |
6 | 111225401304101425 |
7 | 4204541666022344 |
oct | 451031664410731 |
9 | 80243824426158 |
10 | 20413154464217 |
11 | 6560196586069 |
12 | 2358258164875 |
13 | b50c4bcc68c8 |
14 | 5080054b745b |
15 | 255ed6543712 |
hex | 1290ced211d9 |
20413154464217 has 2 divisors, whose sum is σ = 20413154464218. Its totient is φ = 20413154464216.
The previous prime is 20413154464163. The next prime is 20413154464247. The reversal of 20413154464217 is 71246445131402.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19491130095376 + 922024368841 = 4414876^2 + 960221^2 .
It is a cyclic number.
It is not a de Polignac number, because 20413154464217 - 212 = 20413154460121 is a prime.
It is not a weakly prime, because it can be changed into another prime (20413154464247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10206577232108 + 10206577232109.
It is an arithmetic number, because the mean of its divisors is an integer number (10206577232109).
Almost surely, 220413154464217 is an apocalyptic number.
It is an amenable number.
20413154464217 is a deficient number, since it is larger than the sum of its proper divisors (1).
20413154464217 is an equidigital number, since it uses as much as digits as its factorization.
20413154464217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 645120, while the sum is 44.
Adding to 20413154464217 its reverse (71246445131402), we get a palindrome (91659599595619).
The spelling of 20413154464217 in words is "twenty trillion, four hundred thirteen billion, one hundred fifty-four million, four hundred sixty-four thousand, two hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •