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204144012131 is a prime number
BaseRepresentation
bin1011111000011111101…
…1100110101101100011
3201111221010222022110012
42332013323212231203
511321041331342011
6233441002355135
720514610321013
oct2760773465543
9644833868405
10204144012131
1179638a77914
12336934bbaab
1316334a24167
149c48601c43
15549c194a8b
hex2f87ee6b63

204144012131 has 2 divisors, whose sum is σ = 204144012132. Its totient is φ = 204144012130.

The previous prime is 204144012073. The next prime is 204144012157. The reversal of 204144012131 is 131210441402.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 204144012131 - 218 = 204143749987 is a prime.

It is a super-2 number, since 2×2041440121312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 204144012097 and 204144012106.

It is not a weakly prime, because it can be changed into another prime (204144012161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102072006065 + 102072006066.

It is an arithmetic number, because the mean of its divisors is an integer number (102072006066).

Almost surely, 2204144012131 is an apocalyptic number.

204144012131 is a deficient number, since it is larger than the sum of its proper divisors (1).

204144012131 is an equidigital number, since it uses as much as digits as its factorization.

204144012131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 204144012131 its reverse (131210441402), we get a palindrome (335354453533).

The spelling of 204144012131 in words is "two hundred four billion, one hundred forty-four million, twelve thousand, one hundred thirty-one".