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2043430501537 is a prime number
BaseRepresentation
bin11101101111000101111…
…100101111110010100001
321020100110011222220220001
4131233011330233302201
5231434421202022122
64202423343220001
7300430053451045
oct35570574576241
97210404886801
102043430501537
11718683278467
122900448a7601
1311a90525baa9
1470c8c8c8025
153824ac44527
hex1dbc5f2fca1

2043430501537 has 2 divisors, whose sum is σ = 2043430501538. Its totient is φ = 2043430501536.

The previous prime is 2043430501517. The next prime is 2043430501577. The reversal of 2043430501537 is 7351050343402.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1797291478161 + 246139023376 = 1340631^2 + 496124^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2043430501537 is a prime.

It is a super-2 number, since 2×20434305015372 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2043430501496 and 2043430501505.

It is not a weakly prime, because it can be changed into another prime (2043430501517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1021715250768 + 1021715250769.

It is an arithmetic number, because the mean of its divisors is an integer number (1021715250769).

Almost surely, 22043430501537 is an apocalyptic number.

It is an amenable number.

2043430501537 is a deficient number, since it is larger than the sum of its proper divisors (1).

2043430501537 is an equidigital number, since it uses as much as digits as its factorization.

2043430501537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 37.

Adding to 2043430501537 its reverse (7351050343402), we get a palindrome (9394480844939).

The spelling of 2043430501537 in words is "two trillion, forty-three billion, four hundred thirty million, five hundred one thousand, five hundred thirty-seven".