Base | Representation |
---|---|
bin | 1001010011000000001101… |
… | …01000111001011101111011 |
3 | 2200101102221100210112020021 |
4 | 10221200012220321131323 |
5 | 10134424112330312103 |
6 | 111251525424311311 |
7 | 4210020144214132 |
oct | 451400650713573 |
9 | 80342840715207 |
10 | 20444155713403 |
11 | 6572354a16464 |
12 | 236226a472537 |
13 | b53b4c945636 |
14 | 5097068b6919 |
15 | 256becee8bbd |
hex | 129806a3977b |
20444155713403 has 2 divisors, whose sum is σ = 20444155713404. Its totient is φ = 20444155713402.
The previous prime is 20444155713347. The next prime is 20444155713431. The reversal of 20444155713403 is 30431755144402.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20444155713403 - 29 = 20444155712891 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20444155713403.
It is not a weakly prime, because it can be changed into another prime (20444155713463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10222077856701 + 10222077856702.
It is an arithmetic number, because the mean of its divisors is an integer number (10222077856702).
Almost surely, 220444155713403 is an apocalyptic number.
20444155713403 is a deficient number, since it is larger than the sum of its proper divisors (1).
20444155713403 is an equidigital number, since it uses as much as digits as its factorization.
20444155713403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 806400, while the sum is 43.
The spelling of 20444155713403 in words is "twenty trillion, four hundred forty-four billion, one hundred fifty-five million, seven hundred thirteen thousand, four hundred three".
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