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20451113 is a prime number
BaseRepresentation
bin100111000000…
…0111100101001
31102111000122122
41032000330221
520213413423
62010201025
7335555144
oct116007451
942430578
1020451113
11105a9251
126a23175
134310867
142a0505b
151bde8c8
hex1380f29

20451113 has 2 divisors, whose sum is σ = 20451114. Its totient is φ = 20451112.

The previous prime is 20451097. The next prime is 20451127. The reversal of 20451113 is 31115402.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18593344 + 1857769 = 4312^2 + 1363^2 .

It is a cyclic number.

It is not a de Polignac number, because 20451113 - 24 = 20451097 is a prime.

It is a super-4 number, since 4×204511134 (a number of 30 digits) contains 4444 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 20451091 and 20451100.

It is not a weakly prime, because it can be changed into another prime (20450113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10225556 + 10225557.

It is an arithmetic number, because the mean of its divisors is an integer number (10225557).

Almost surely, 220451113 is an apocalyptic number.

It is an amenable number.

20451113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20451113 is an equidigital number, since it uses as much as digits as its factorization.

20451113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 20451113 is about 4522.2906806175. The cubic root of 20451113 is about 273.4674553283.

Adding to 20451113 its reverse (31115402), we get a palindrome (51566515).

The spelling of 20451113 in words is "twenty million, four hundred fifty-one thousand, one hundred thirteen".