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20504051443055 = 537591878520517
BaseRepresentation
bin1001010100101111110001…
…01100111110010101101111
32200121011112121011211221202
410222113320230332111233
510141414244132134210
6111335233045520115
74214240336422505
oct452277054762557
980534477154852
1020504051443055
1165957a0555684
1223719a541303b
13b596a68c539b
1450c589586675
152585565019a5
hex12a5f8b3e56f

20504051443055 has 16 divisors (see below), whose sum is σ = 25698160686240. Its totient is φ = 15689403349632.

The previous prime is 20504051443033. The next prime is 20504051443093. The reversal of 20504051443055 is 55034415040502.

It is a cyclic number.

It is not a de Polignac number, because 20504051443055 - 26 = 20504051442991 is a prime.

It is a super-2 number, since 2×205040514430552 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 939249344 + ... + 939271173.

It is an arithmetic number, because the mean of its divisors is an integer number (1606135042890).

Almost surely, 220504051443055 is an apocalyptic number.

20504051443055 is a deficient number, since it is larger than the sum of its proper divisors (5194109243185).

20504051443055 is a wasteful number, since it uses less digits than its factorization.

20504051443055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1878520618.

The product of its (nonzero) digits is 240000, while the sum is 38.

Adding to 20504051443055 its reverse (55034415040502), we get a palindrome (75538466483557).

The spelling of 20504051443055 in words is "twenty trillion, five hundred four billion, fifty-one million, four hundred forty-three thousand, fifty-five".

Divisors: 1 5 37 59 185 295 2183 10915 1878520517 9392602585 69505259129 110832710503 347526295645 554163552515 4100810288611 20504051443055