Base | Representation |
---|---|
bin | 11101111011010001111… |
… | …100011010111001010001 |
3 | 21021121020011212212012011 |
4 | 131323101330122321101 |
5 | 232143221230110213 |
6 | 4212430052502521 |
7 | 301402254025126 |
oct | 35732174327121 |
9 | 7247204785164 |
10 | 2056516644433 |
11 | 72318903a299 |
12 | 29269731aa41 |
13 | 11bc0c431c04 |
14 | 7177087874d |
15 | 38764a1003d |
hex | 1ded1f1ae51 |
2056516644433 has 2 divisors, whose sum is σ = 2056516644434. Its totient is φ = 2056516644432.
The previous prime is 2056516644419. The next prime is 2056516644463. The reversal of 2056516644433 is 3344466156502.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1466465294529 + 590051349904 = 1210977^2 + 768148^2 .
It is a cyclic number.
It is not a de Polignac number, because 2056516644433 - 25 = 2056516644401 is a prime.
It is a super-2 number, since 2×20565166444332 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2056516644463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1028258322216 + 1028258322217.
It is an arithmetic number, because the mean of its divisors is an integer number (1028258322217).
Almost surely, 22056516644433 is an apocalyptic number.
It is an amenable number.
2056516644433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2056516644433 is an equidigital number, since it uses as much as digits as its factorization.
2056516644433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6220800, while the sum is 49.
The spelling of 2056516644433 in words is "two trillion, fifty-six billion, five hundred sixteen million, six hundred forty-four thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •