Base | Representation |
---|---|
bin | 11110100011110001110… |
… | …000101110010100100011 |
3 | 21102202110121201101202202 |
4 | 132203301300232110203 |
5 | 233401300012402042 |
6 | 4244420550403415 |
7 | 304501650342464 |
oct | 36436160562443 |
9 | 7382417641682 |
10 | 2100000122147 |
11 | 73a67235a734 |
12 | 29abb196056b |
13 | 12304c0b7595 |
14 | 738d7942d6b |
15 | 3995c23d632 |
hex | 1e8f1c2e523 |
2100000122147 has 2 divisors, whose sum is σ = 2100000122148. Its totient is φ = 2100000122146.
The previous prime is 2100000122069. The next prime is 2100000122221. The reversal of 2100000122147 is 7412210000012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2100000122147 - 228 = 2099731686691 is a prime.
It is not a weakly prime, because it can be changed into another prime (2100000122347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050000061073 + 1050000061074.
It is an arithmetic number, because the mean of its divisors is an integer number (1050000061074).
Almost surely, 22100000122147 is an apocalyptic number.
2100000122147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100000122147 is an equidigital number, since it uses as much as digits as its factorization.
2100000122147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 20.
Adding to 2100000122147 its reverse (7412210000012), we get a palindrome (9512210122159).
The spelling of 2100000122147 in words is "two trillion, one hundred billion, one hundred twenty-two thousand, one hundred forty-seven".
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