Base | Representation |
---|---|
bin | 1001100011001011111100… |
… | …01000010001111101000011 |
3 | 2202100121012211022111212021 |
4 | 10301211332020101331003 |
5 | 10223031413032210201 |
6 | 112355210331342311 |
7 | 4265133545024443 |
oct | 461457610217503 |
9 | 82317184274767 |
10 | 21000211210051 |
11 | 6767159832197 |
12 | 2431b942b1997 |
13 | b94408260128 |
14 | 5285b6764123 |
15 | 2663e4e1cea1 |
hex | 13197e211f43 |
21000211210051 has 2 divisors, whose sum is σ = 21000211210052. Its totient is φ = 21000211210050.
The previous prime is 21000211210021. The next prime is 21000211210189. The reversal of 21000211210051 is 15001211200012.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21000211210051 - 25 = 21000211210019 is a prime.
It is not a weakly prime, because it can be changed into another prime (21000211210021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10500105605025 + 10500105605026.
It is an arithmetic number, because the mean of its divisors is an integer number (10500105605026).
Almost surely, 221000211210051 is an apocalyptic number.
21000211210051 is a deficient number, since it is larger than the sum of its proper divisors (1).
21000211210051 is an equidigital number, since it uses as much as digits as its factorization.
21000211210051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 21000211210051 its reverse (15001211200012), we get a palindrome (36001422410063).
The spelling of 21000211210051 in words is "twenty-one trillion, two hundred eleven million, two hundred ten thousand, fifty-one".
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