Base | Representation |
---|---|
bin | 101111110000000011000100… |
… | …000110110000100001001011 |
3 | 1000112120202112202100100222102 |
4 | 233300003010012300201023 |
5 | 210011301000304324042 |
6 | 2022353133413144015 |
7 | 62143502564114414 |
oct | 5760030406604113 |
9 | 1015522482310872 |
10 | 210010011011147 |
11 | 60a088222a21a6 |
12 | 1b67941b92b00b |
13 | 9024b2248b729 |
14 | 39c077854080b |
15 | 1942c97d17b32 |
hex | bf00c41b084b |
210010011011147 has 2 divisors, whose sum is σ = 210010011011148. Its totient is φ = 210010011011146.
The previous prime is 210010011011137. The next prime is 210010011011231. The reversal of 210010011011147 is 741110110010012.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 210010011011147 - 24 = 210010011011131 is a prime.
It is not a weakly prime, because it can be changed into another prime (210010011011137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105005005505573 + 105005005505574.
It is an arithmetic number, because the mean of its divisors is an integer number (105005005505574).
Almost surely, 2210010011011147 is an apocalyptic number.
210010011011147 is a deficient number, since it is larger than the sum of its proper divisors (1).
210010011011147 is an equidigital number, since it uses as much as digits as its factorization.
210010011011147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 210010011011147 its reverse (741110110010012), we get a palindrome (951120121021159).
The spelling of 210010011011147 in words is "two hundred ten trillion, ten billion, eleven million, eleven thousand, one hundred forty-seven".
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