Base | Representation |
---|---|
bin | 1001100011001101011010… |
… | …01101100001000111001011 |
3 | 2202100200020212122200122102 |
4 | 10301212231031201013023 |
5 | 10223040022241041021 |
6 | 112355420545544015 |
7 | 4265162246052554 |
oct | 461465515410713 |
9 | 82320225580572 |
10 | 21001001112011 |
11 | 67675246a6228 |
12 | 243217494500b |
13 | b94502ab893b |
14 | 52864d62132b |
15 | 26643e44d00b |
hex | 1319ad3611cb |
21001001112011 has 2 divisors, whose sum is σ = 21001001112012. Its totient is φ = 21001001112010.
The previous prime is 21001001111957. The next prime is 21001001112043. The reversal of 21001001112011 is 11021110010012.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21001001112011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21001001111983 and 21001001112001.
It is not a weakly prime, because it can be changed into another prime (21001001112811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10500500556005 + 10500500556006.
It is an arithmetic number, because the mean of its divisors is an integer number (10500500556006).
Almost surely, 221001001112011 is an apocalyptic number.
21001001112011 is a deficient number, since it is larger than the sum of its proper divisors (1).
21001001112011 is an equidigital number, since it uses as much as digits as its factorization.
21001001112011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 21001001112011 its reverse (11021110010012), we get a palindrome (32022111122023).
The spelling of 21001001112011 in words is "twenty-one trillion, one billion, one million, one hundred twelve thousand, eleven".
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