Base | Representation |
---|---|
bin | 101111110000000100001011… |
… | …001010001010111101110011 |
3 | 1000112120212121211110011022222 |
4 | 233300010023022022331303 |
5 | 210011310420442310433 |
6 | 2022353451555351255 |
7 | 62143544250444014 |
oct | 5760041312127563 |
9 | 1015525554404288 |
10 | 210011203088243 |
11 | 60a09284187387 |
12 | 1b6796b2bb252b |
13 | 9024c8243a8ab |
14 | 39c084c9ab00b |
15 | 1942d177dab98 |
hex | bf010b28af73 |
210011203088243 has 2 divisors, whose sum is σ = 210011203088244. Its totient is φ = 210011203088242.
The previous prime is 210011203088161. The next prime is 210011203088263. The reversal of 210011203088243 is 342880302110012.
210011203088243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 210011203088243 - 210 = 210011203087219 is a prime.
It is not a weakly prime, because it can be changed into another prime (210011203088263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105005601544121 + 105005601544122.
It is an arithmetic number, because the mean of its divisors is an integer number (105005601544122).
Almost surely, 2210011203088243 is an apocalyptic number.
210011203088243 is a deficient number, since it is larger than the sum of its proper divisors (1).
210011203088243 is an equidigital number, since it uses as much as digits as its factorization.
210011203088243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 35.
Adding to 210011203088243 its reverse (342880302110012), we get a palindrome (552891505198255).
The spelling of 210011203088243 in words is "two hundred ten trillion, eleven billion, two hundred three million, eighty-eight thousand, two hundred forty-three".
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