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2100120131103 = 3700040043701
BaseRepresentation
bin11110100011111000111…
…010100001011000011111
321102202202222112111002220
4132203320322201120133
5233402021223143403
64244440514520423
7304504635402021
oct36437072413037
97382688474086
102100120131103
1173a724078195
1229b025b96113
1312306ac155b7
1473909862011
1539967a46953
hex1e8f8ea161f

2100120131103 has 4 divisors (see below), whose sum is σ = 2800160174808. Its totient is φ = 1400080087400.

The previous prime is 2100120131003. The next prime is 2100120131141. The reversal of 2100120131103 is 3011310210012.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2100120131103 - 28 = 2100120130847 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2100120131003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350020021848 + ... + 350020021853.

It is an arithmetic number, because the mean of its divisors is an integer number (700040043702).

Almost surely, 22100120131103 is an apocalyptic number.

2100120131103 is a deficient number, since it is larger than the sum of its proper divisors (700040043705).

2100120131103 is an equidigital number, since it uses as much as digits as its factorization.

2100120131103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 700040043704.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 2100120131103 its reverse (3011310210012), we get a palindrome (5111430341115).

The spelling of 2100120131103 in words is "two trillion, one hundred billion, one hundred twenty million, one hundred thirty-one thousand, one hundred three".

Divisors: 1 3 700040043701 2100120131103