Base | Representation |
---|---|
bin | 11110100011111001000… |
… | …001101111100011000011 |
3 | 21102202210010002122212001 |
4 | 132203321001233203003 |
5 | 233402022214233011 |
6 | 4244441023244431 |
7 | 304504660445035 |
oct | 36437101574303 |
9 | 7382703078761 |
10 | 2100122024131 |
11 | 73a72515047a |
12 | 29b026749717 |
13 | 12306b429131 |
14 | 73909bd5c55 |
15 | 39967cbc7c1 |
hex | 1e8f906f8c3 |
2100122024131 has 2 divisors, whose sum is σ = 2100122024132. Its totient is φ = 2100122024130.
The previous prime is 2100122024081. The next prime is 2100122024137. The reversal of 2100122024131 is 1314202210012.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2100122024131 is a prime.
It is a super-2 number, since 2×21001220241312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2100122024099 and 2100122024108.
It is not a weakly prime, because it can be changed into another prime (2100122024137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050061012065 + 1050061012066.
It is an arithmetic number, because the mean of its divisors is an integer number (1050061012066).
Almost surely, 22100122024131 is an apocalyptic number.
2100122024131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100122024131 is an equidigital number, since it uses as much as digits as its factorization.
2100122024131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 2100122024131 its reverse (1314202210012), we get a palindrome (3414324234143).
The spelling of 2100122024131 in words is "two trillion, one hundred billion, one hundred twenty-two million, twenty-four thousand, one hundred thirty-one".
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