Search a number
-
+
2100122024131 is a prime number
BaseRepresentation
bin11110100011111001000…
…001101111100011000011
321102202210010002122212001
4132203321001233203003
5233402022214233011
64244441023244431
7304504660445035
oct36437101574303
97382703078761
102100122024131
1173a72515047a
1229b026749717
1312306b429131
1473909bd5c55
1539967cbc7c1
hex1e8f906f8c3

2100122024131 has 2 divisors, whose sum is σ = 2100122024132. Its totient is φ = 2100122024130.

The previous prime is 2100122024081. The next prime is 2100122024137. The reversal of 2100122024131 is 1314202210012.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2100122024131 is a prime.

It is a super-2 number, since 2×21001220241312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2100122024099 and 2100122024108.

It is not a weakly prime, because it can be changed into another prime (2100122024137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050061012065 + 1050061012066.

It is an arithmetic number, because the mean of its divisors is an integer number (1050061012066).

Almost surely, 22100122024131 is an apocalyptic number.

2100122024131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2100122024131 is an equidigital number, since it uses as much as digits as its factorization.

2100122024131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 2100122024131 its reverse (1314202210012), we get a palindrome (3414324234143).

The spelling of 2100122024131 in words is "two trillion, one hundred billion, one hundred twenty-two million, twenty-four thousand, one hundred thirty-one".