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21001300111 = 111909209101
BaseRepresentation
bin10011100011110001…
…100110100010001111
32000012121122120210001
4103203301212202033
5321002313100421
613351534425131
71342301051131
oct234361464217
960177576701
1021001300111
1189a7760680
1240a13621a7
131c98c7b7cc
141033291051
1582db07691
hex4e3c6688f

21001300111 has 4 divisors (see below), whose sum is σ = 22910509224. Its totient is φ = 19092091000.

The previous prime is 21001300093. The next prime is 21001300169. The reversal of 21001300111 is 11100310012.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21001300111 is a prime.

It is a super-2 number, since 2×210013001112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21001300171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 954604540 + ... + 954604561.

It is an arithmetic number, because the mean of its divisors is an integer number (5727627306).

Almost surely, 221001300111 is an apocalyptic number.

21001300111 is a deficient number, since it is larger than the sum of its proper divisors (1909209113).

21001300111 is a wasteful number, since it uses less digits than its factorization.

21001300111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1909209112.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 21001300111 its reverse (11100310012), we get a palindrome (32101610123).

Subtracting from 21001300111 its reverse (11100310012), we obtain a palindrome (9900990099).

The spelling of 21001300111 in words is "twenty-one billion, one million, three hundred thousand, one hundred eleven".

Divisors: 1 11 1909209101 21001300111