Base | Representation |
---|---|
bin | 11110100011111110010… |
… | …101111111111010011011 |
3 | 21102210000022221021202022 |
4 | 132203332111333322123 |
5 | 233402213033020443 |
6 | 4244453531125055 |
7 | 304510122551462 |
oct | 36437625777233 |
9 | 7383008837668 |
10 | 2100211220123 |
11 | 73a770532775 |
12 | 29b0505a378b |
13 | 123083a59123 |
14 | 739179b39d9 |
15 | 39970a3ae68 |
hex | 1e8fe57fe9b |
2100211220123 has 4 divisors (see below), whose sum is σ = 2144896565280. Its totient is φ = 2055525874968.
The previous prime is 2100211220057. The next prime is 2100211220227. The reversal of 2100211220123 is 3210221120012.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2100211220123 - 220 = 2100210171547 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2100211228123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22342672508 + ... + 22342672601.
It is an arithmetic number, because the mean of its divisors is an integer number (536224141320).
Almost surely, 22100211220123 is an apocalyptic number.
2100211220123 is a deficient number, since it is larger than the sum of its proper divisors (44685345157).
2100211220123 is an equidigital number, since it uses as much as digits as its factorization.
2100211220123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44685345156.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2100211220123 its reverse (3210221120012), we get a palindrome (5310432340135).
The spelling of 2100211220123 in words is "two trillion, one hundred billion, two hundred eleven million, two hundred twenty thousand, one hundred twenty-three".
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