21003140545534 has 8 divisors (see below), whose sum is σ = 36005383792368. Its totient is φ = 9001345948080.

The previous prime is 21003140545531. The next prime is 21003140545559. The reversal of 21003140545534 is 43554504130012.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×21003140545534³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 21003140545493 and 21003140545502.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21003140545531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 750112162327 + ... + 750112162354.

It is an arithmetic number, because the mean of its divisors is an integer number (4500672974046).

Almost surely, 2^{21003140545534} is an apocalyptic number.

21003140545534 is a deficient number, since it is larger than the sum of its proper divisors (15002243246834).

21003140545534 is a wasteful number, since it uses less digits than its factorization.

21003140545534 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1500224324690.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 21003140545534 its reverse (43554504130012), we get a palindrome (64557644675546).

The spelling of 21003140545534 in words is "twenty-one trillion, three billion, one hundred forty million, five hundred forty-five thousand, five hundred thirty-four".