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21003140550005 = 597166619259907
BaseRepresentation
bin1001100011010001011001…
…01110110100110101110101
32202100212202222101101211122
410301220230232310311311
510223103412440100010
6112400413133313325
74265266255014245
oct461505456646565
982325688341748
1021003140550005
1167684223206a9
122432671335845
13b94784104593
145287b3815b25
152665171a5855
hex131a2cbb4d75

21003140550005 has 16 divisors (see below), whose sum is σ = 25463852124480. Its totient is φ = 16629126876672.

The previous prime is 21003140549987. The next prime is 21003140550031. The reversal of 21003140550005 is 50005504130012.

It is a cyclic number.

It is not a de Polignac number, because 21003140550005 - 210 = 21003140548981 is a prime.

It is a super-2 number, since 2×210031405500052 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 80680262 + ... + 80940168.

It is an arithmetic number, because the mean of its divisors is an integer number (1591490757780).

Almost surely, 221003140550005 is an apocalyptic number.

It is an amenable number.

21003140550005 is a deficient number, since it is larger than the sum of its proper divisors (4460711574475).

21003140550005 is a wasteful number, since it uses less digits than its factorization.

21003140550005 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 426628.

The product of its (nonzero) digits is 3000, while the sum is 26.

Adding to 21003140550005 its reverse (50005504130012), we get a palindrome (71008644680017).

The spelling of 21003140550005 in words is "twenty-one trillion, three billion, one hundred forty million, five hundred fifty thousand, five".

Divisors: 1 5 97 485 166619 259907 833095 1299535 16162043 25210979 80810215 126054895 43305444433 216527222165 4200628110001 21003140550005