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21004134141301 = 198147135691757
BaseRepresentation
bin1001100011010011001111…
…11101000100110101110101
32202100222100020000001212021
410301221213331010311311
510223112431320010201
6112401055505353141
74265333011264003
oct461514775046565
982328306001767
1021004134141301
116768892167533
1224328aa0387b1
13b948b1c0971c
14528869775a73
1526657451cea1
hex131a67f44d75

21004134141301 has 8 divisors (see below), whose sum is σ = 22112328883680. Its totient is φ = 19896210798768.

The previous prime is 21004134141247. The next prime is 21004134141313. The reversal of 21004134141301 is 10314143140012.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21004134141301 - 27 = 21004134141173 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21004132141301) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 67691086 + ... + 68000671.

It is an arithmetic number, because the mean of its divisors is an integer number (2764041110460).

Almost surely, 221004134141301 is an apocalyptic number.

It is an amenable number.

21004134141301 is a deficient number, since it is larger than the sum of its proper divisors (1108194742379).

21004134141301 is a wasteful number, since it uses less digits than its factorization.

21004134141301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 135699923.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 21004134141301 its reverse (10314143140012), we get a palindrome (31318277281313).

The spelling of 21004134141301 in words is "twenty-one trillion, four billion, one hundred thirty-four million, one hundred forty-one thousand, three hundred one".

Divisors: 1 19 8147 154793 135691757 2578143383 1105480744279 21004134141301