Base | Representation |
---|---|
bin | 11110100100001010011… |
… | …001010011101011110011 |
3 | 21102210112102101210210021 |
4 | 132210022121103223303 |
5 | 233403121313223011 |
6 | 4244525552544311 |
7 | 304515126304414 |
oct | 36441231235363 |
9 | 7383472353707 |
10 | 2100413414131 |
11 | 73a86468405a |
12 | 29b0a8252097 |
13 | 1230b6900c56 |
14 | 739367a780b |
15 | 3998367a471 |
hex | 1e90a653af3 |
2100413414131 has 16 divisors (see below), whose sum is σ = 2225476503360. Its totient is φ = 1975518576640.
The previous prime is 2100413414101. The next prime is 2100413414153. The reversal of 2100413414131 is 1314143140012.
It is a cyclic number.
It is not a de Polignac number, because 2100413414131 - 27 = 2100413414003 is a prime.
It is a super-2 number, since 2×21004134141312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2100413414096 and 2100413414105.
It is not an unprimeable number, because it can be changed into a prime (2100413414101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 216109290 + ... + 216119008.
It is an arithmetic number, because the mean of its divisors is an integer number (139092281460).
Almost surely, 22100413414131 is an apocalyptic number.
2100413414131 is a deficient number, since it is larger than the sum of its proper divisors (125063089229).
2100413414131 is a wasteful number, since it uses less digits than its factorization.
2100413414131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17054.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 2100413414131 its reverse (1314143140012), we get a palindrome (3414556554143).
The spelling of 2100413414131 in words is "two trillion, one hundred billion, four hundred thirteen million, four hundred fourteen thousand, one hundred thirty-one".
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