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2100413414101 is a prime number
BaseRepresentation
bin11110100100001010011…
…001010011101011010101
321102210112102101210202011
4132210022121103223111
5233403121313222401
64244525552544221
7304515126304342
oct36441231235325
97383472353664
102100413414101
1173a864684032
1229b0a8252071
131230b6900c32
14739367a77c9
153998367a451
hex1e90a653ad5

2100413414101 has 2 divisors, whose sum is σ = 2100413414102. Its totient is φ = 2100413414100.

The previous prime is 2100413414087. The next prime is 2100413414153. The reversal of 2100413414101 is 1014143140012.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1383978133476 + 716435280625 = 1176426^2 + 846425^2 .

It is a cyclic number.

It is not a de Polignac number, because 2100413414101 - 215 = 2100413381333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2100413414201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050206707050 + 1050206707051.

It is an arithmetic number, because the mean of its divisors is an integer number (1050206707051).

Almost surely, 22100413414101 is an apocalyptic number.

It is an amenable number.

2100413414101 is a deficient number, since it is larger than the sum of its proper divisors (1).

2100413414101 is an equidigital number, since it uses as much as digits as its factorization.

2100413414101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 2100413414101 its reverse (1014143140012), we get a palindrome (3114556554113).

The spelling of 2100413414101 in words is "two trillion, one hundred billion, four hundred thirteen million, four hundred fourteen thousand, one hundred one".