Base | Representation |
---|---|
bin | 11110100100001010011… |
… | …001010011101011010101 |
3 | 21102210112102101210202011 |
4 | 132210022121103223111 |
5 | 233403121313222401 |
6 | 4244525552544221 |
7 | 304515126304342 |
oct | 36441231235325 |
9 | 7383472353664 |
10 | 2100413414101 |
11 | 73a864684032 |
12 | 29b0a8252071 |
13 | 1230b6900c32 |
14 | 739367a77c9 |
15 | 3998367a451 |
hex | 1e90a653ad5 |
2100413414101 has 2 divisors, whose sum is σ = 2100413414102. Its totient is φ = 2100413414100.
The previous prime is 2100413414087. The next prime is 2100413414153. The reversal of 2100413414101 is 1014143140012.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1383978133476 + 716435280625 = 1176426^2 + 846425^2 .
It is a cyclic number.
It is not a de Polignac number, because 2100413414101 - 215 = 2100413381333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2100413414201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050206707050 + 1050206707051.
It is an arithmetic number, because the mean of its divisors is an integer number (1050206707051).
Almost surely, 22100413414101 is an apocalyptic number.
It is an amenable number.
2100413414101 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100413414101 is an equidigital number, since it uses as much as digits as its factorization.
2100413414101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 2100413414101 its reverse (1014143140012), we get a palindrome (3114556554113).
The spelling of 2100413414101 in words is "two trillion, one hundred billion, four hundred thirteen million, four hundred fourteen thousand, one hundred one".
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