Base | Representation |
---|---|
bin | 11110100100001011011… |
… | …001111000010011001011 |
3 | 21102210120121020210112022 |
4 | 132210023121320103023 |
5 | 233403140131410243 |
6 | 4244531355435055 |
7 | 304515423215006 |
oct | 36441331702313 |
9 | 7383517223468 |
10 | 2100430341323 |
11 | 73a873195776 |
12 | 29b0b1a55a8b |
13 | 1230ba279842 |
14 | 73938b3253d |
15 | 39984dc0b68 |
hex | 1e90b6784cb |
2100430341323 has 2 divisors, whose sum is σ = 2100430341324. Its totient is φ = 2100430341322.
The previous prime is 2100430341307. The next prime is 2100430341391. The reversal of 2100430341323 is 3231430340012.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2100430341323 - 24 = 2100430341307 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2100430341292 and 2100430341301.
It is not a weakly prime, because it can be changed into another prime (2100432341323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050215170661 + 1050215170662.
It is an arithmetic number, because the mean of its divisors is an integer number (1050215170662).
Almost surely, 22100430341323 is an apocalyptic number.
2100430341323 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100430341323 is an equidigital number, since it uses as much as digits as its factorization.
2100430341323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 2100430341323 its reverse (3231430340012), we get a palindrome (5331860681335).
The spelling of 2100430341323 in words is "two trillion, one hundred billion, four hundred thirty million, three hundred forty-one thousand, three hundred twenty-three".
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