Base | Representation |
---|---|
bin | 10011100011111101… |
… | …001010100011000011 |
3 | 2000012211100120122201 |
4 | 103203331022203003 |
5 | 321004102044303 |
6 | 13352123414031 |
7 | 1342335604132 |
oct | 234375124303 |
9 | 60184316581 |
10 | 21004331203 |
11 | 89a9440a09 |
12 | 40a2384317 |
13 | 1c997a035b |
14 | 103383d919 |
15 | 82e00581d |
hex | 4e3f4a8c3 |
21004331203 has 2 divisors, whose sum is σ = 21004331204. Its totient is φ = 21004331202.
The previous prime is 21004331171. The next prime is 21004331233. The reversal of 21004331203 is 30213340012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21004331203 - 25 = 21004331171 is a prime.
It is not a weakly prime, because it can be changed into another prime (21004331233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10502165601 + 10502165602.
It is an arithmetic number, because the mean of its divisors is an integer number (10502165602).
Almost surely, 221004331203 is an apocalyptic number.
21004331203 is a deficient number, since it is larger than the sum of its proper divisors (1).
21004331203 is an equidigital number, since it uses as much as digits as its factorization.
21004331203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 21004331203 its reverse (30213340012), we get a palindrome (51217671215).
The spelling of 21004331203 in words is "twenty-one billion, four million, three hundred thirty-one thousand, two hundred three".
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