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2100440011 = 4744690213
BaseRepresentation
bin111110100110010…
…0010101111001011
312102101100102000111
41331030202233023
513300203040021
6544231415151
7103023305545
oct17514425713
95371312014
102100440011
1198870973a
124a75244b7
13276213217
1415cd62695
15c46028e1
hex7d322bcb

2100440011 has 4 divisors (see below), whose sum is σ = 2145130272. Its totient is φ = 2055749752.

The previous prime is 2100440003. The next prime is 2100440029. The reversal of 2100440011 is 1100440012.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2100440011 - 23 = 2100440003 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2100439973 and 2100440000.

It is not an unprimeable number, because it can be changed into a prime (2100440051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22345060 + ... + 22345153.

It is an arithmetic number, because the mean of its divisors is an integer number (536282568).

Almost surely, 22100440011 is an apocalyptic number.

2100440011 is a deficient number, since it is larger than the sum of its proper divisors (44690261).

2100440011 is an equidigital number, since it uses as much as digits as its factorization.

2100440011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44690260.

The product of its (nonzero) digits is 32, while the sum is 13.

The square root of 2100440011 is about 45830.5576117071. The cubic root of 2100440011 is about 1280.6685982524.

Adding to 2100440011 its reverse (1100440012), we get a palindrome (3200880023).

Subtracting from 2100440011 its reverse (1100440012), we obtain a palindrome (999999999).

The spelling of 2100440011 in words is "two billion, one hundred million, four hundred forty thousand, eleven".

Divisors: 1 47 44690213 2100440011